Rohm BA6209 free download

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Motor driver ICs Reversible motor driver BA6209 / BA6209N The BA6209 and BA6209N are reversible-motor drivers suitable for brush motors. Two logic inputs allow three output modes : forward, reverse, and braking. The motor revolving speed can be set arbitrarily by controlling the voltage applied to the motor with the control pin voltage VR. FApplications VCRs and cassette tape recorders FFeatures 1) Power transistors can handle a large current (1.6A maximally). 2) Brake is applied when stopping the motor. 3) Built-in function to absorb rush currents generated by reversing and braking. 4) Motor speed controlling pin. FBlock diagram 5) Small standby current. (VCC = 12V, IO = 5.5mA typically) 6) Stable operation during mode changes either from forward to reverse or vice versa. 7) Interface with CMOS devices. 386 Motor driver ICs FAbsolute maximum ratings (Ta = 25_C) BA6209 / BA6209N FRecommended operating conditions (Ta = 25_C) FElectrical characteristics (unless otherwise noted, Ta = 25_C and VCC = 12V) FElectrical characteristic curves 387 Motor driver ICs BA6209 / BA6209N 388 Motor driver ICs BA6209 / BA6209N FMeasurement circuit 389 Motor driver ICs FCircuit operation Input / output truth table BA6209 / BA6209N Forward / reverse control, forced stop, and rush current absorption are controlled by the combination of FIN and RIN input states. (1) Forward / reverse control circuit When FIN is HIGH and RIN is LOW, current flows from OUT1 to OUT2. When FIN is LOW and RIN is HIGH, current flows from OUT2 to OUT1 (refer to the truth table). (2) Forced stop circuit By setting RIN and FIN both HIGH or both LOW, power supply to the motor is shut down and a brake is applied by absorbing the motor counter-electromotive force. FPin descriptions (3) Rush current absorption circuit When a high voltage (caused by such as a motor reversal) is generated on OUT1 and OUT2, an internal comparator detects the high voltage and turns on an internal circuit that absorbs rush currents. (4) Drive circuit The forward direction of the motor connected between OUT1 and OUT2 corresponds to the current flow from OUT1 to OUT2, and the reverse direction corresponds to the current flow from OUT2 to OUT1. The output voltage (VOUT) applied to the motor is given by the equation : VOUT (V) = VZD * VCE (sat.) = VZD * 0.2 (IOUT = 100mA) where VZD is the zener voltage of the constant voltage diode (ZD) connected to pin 4. If Vref is left OPEN, the output voltage (VOUT) is given by the equation : VOUT (V) = VCC1 * VCE (sat.) (PNP) * 2VF * VCE (sat.) = VCC1 * 1.8 (IOUT = 100mA) 390 Motor driver ICs FOperation notes (1) Resistor dividing IC power consumption To reduce power dissipated in the IC, a resistance (about 3X10) must always be connected between VCC and the power supply pin of the driver circuit. If VCC2 is connected to VCC with no resistor, the IC can be damaged by overcurrent when operated at the voltage range close to the maximum operating voltage. (2) Control